find the critical numbers of the function f(x)= x^6(x-4)^5
i found the derivative of the dunctions (x-4)^4(x^5)(11x-24)
and than equating f'(x)=0
x=4 , 0 , 24/11
yep!
but i also have to describe the behavior at the critical points
whether it has a maximum or minimum
at x=4 would it be minimum?
Since you are given a graph you don't actually need to find g'' just look at small intervals around those critical numbers do those critical numbers stand higher or lower on those sub-intervals
or f'' (not g'') sorry
no i had to draw the graph
Well if that is a correct graph, can you tell which or mins and maxs (locally)? And then we can also determine this without a graph too
would 4 be min?
yes because looking at its near neighborhoods he is the lowest around them
the other critical points arent maximum right?
is 0 local maximum?
it seems she as graphed f'(x) @myininaya
yea i did graph f'(x)
just a clarifying question, do you say below point a minimum ? |dw:1410754466706:dw|
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