find the critical numbers of the function f(x)= x^6(x-4)^5
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OpenStudy (anonymous):
i found the derivative of the dunctions (x-4)^4(x^5)(11x-24)
OpenStudy (anonymous):
and than equating f'(x)=0
OpenStudy (anonymous):
x=4 , 0 , 24/11
OpenStudy (rational):
yep!
OpenStudy (anonymous):
but i also have to describe the behavior at the critical points
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OpenStudy (anonymous):
OpenStudy (anonymous):
whether it has a maximum or minimum
OpenStudy (anonymous):
at x=4 would it be minimum?
myininaya (myininaya):
Since you are given a graph you don't actually need to find g''
just look at small intervals around those critical numbers
do those critical numbers stand higher or lower on those sub-intervals
myininaya (myininaya):
or f'' (not g'') sorry
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OpenStudy (anonymous):
no i had to draw the graph
myininaya (myininaya):
Well if that is a correct graph, can you tell which or mins and maxs (locally)?
And then we can also determine this without a graph too
OpenStudy (anonymous):
would 4 be min?
myininaya (myininaya):
yes because looking at its near neighborhoods he is the lowest around them
OpenStudy (anonymous):
the other critical points arent maximum right?
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OpenStudy (anonymous):
is 0 local maximum?
OpenStudy (rational):
it seems she as graphed f'(x) @myininaya
OpenStudy (anonymous):
yea i did graph f'(x)
OpenStudy (rational):
just a clarifying question, do you say below point a minimum ?
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