A juggling bag is thrown straight up into the air and is caught 3s later. A: What is the initial velocity of the ball? B: Calculate the maximum height that it reaches.

Question

campbell_st · Answer

well the initial velocity of the ball is zero as you are juggling bags... 

and it has no max height... as you again are using bags

mrnood · Answer

@Campbell_st
That is not a helpful answer

@fjapusen I suggest you ignore that post

mrnood · Answer

You need the equations for constant acceleration.

In tis case you know:
a = g = 9.81m/s^2
t= 1.5s  (because the bag will take the same time to reach peak as to fall back to catching point)
v (final velocity) = 0 because the bag stops at the top

the equation to solve this is

v= u +at    (solve for u using the above values)

the other equation required is 

s=ut +0.5 at^2

solve this for s (after you have the value for u from the first part)