Question

what is the period of this function?

Answer 1

\[y=\cot x-\tan x -2\tan2x\]

Answer 2

I think the period is \[\pi \]

Answer 3

@k142.can you help me,please?

Answer 4

yeah I agree. you must have f(x)=f(x + pi) for pi to be the period. and it is because cot (x + pi) - tan (x + pi) -2tan2(x + pi) = cot x - tan x - 2tan2x

Answer 5

it is 2pi

Answer 6

oops it is pi,, sorry

Answer 7

so period of first function is pi.right?

Answer 8

yes if you mean sin^8x?

Answer 9

no no no no .. it is 2pi why are you making me mess it up?? it is 2pi

Answer 10

since sin^8(x + 2pi) + cos^5(x + 2pi) = sin^8x + cos^5x... and pi cannot be because sin^8(x+pi) + cos^5(x + pi) = sin^8x - cos^5x so it is not the same as the original function.

Answer 11

Have to go! take care!