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Mathematics 16 Online
OpenStudy (anonymous):

i will give medal

OpenStudy (anonymous):

Given that\[f(x)=\frac{ 5-2x }{ 3x }\] Find\[f ^{-1}(x)\]

OpenStudy (john_es):

Let call \[f(x)=y\]Then, \[y=\frac{5-2x}{3x}\] Now you should find the function x(y). In other words, put x in function of y. An example with other function: \[f(x)=2x+3\\ y=2x+3\\ x=(y-3)/2\] Then change x for y, and y for x this way, \[y=(x-3)/2\]But now, \[f^{-1}(x)=(x-3)/2\]

OpenStudy (anonymous):

But the answer is \[\frac{ 5 }{ 3x+2 }\]

OpenStudy (john_es):

The answer I gave you was for an example. You should do the same process for your problem.

OpenStudy (john_es):

Do you understand it or need some more help?

OpenStudy (anonymous):

yes please can u?

OpenStudy (john_es):

Ok, the, first, we will find x(y), \[y=\frac{5-2x}{3x}\Rightarrow 3xy=5-2x\Rightarrow3xy+2x=5\Rightarrow\\ \Rightarrow x(3y+2)=5\Rightarrow x=\frac{5}{2+3y}\] Now, simply change x for y, and y for x, and you'll obtain the result.

OpenStudy (anonymous):

even i was getting the same thing but i wasn't know to change x for y and y for x

OpenStudy (anonymous):

any way thanks a lot

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