i will give medal
Given that\[f(x)=\frac{ 5-2x }{ 3x }\] Find\[f ^{-1}(x)\]
Let call \[f(x)=y\]Then, \[y=\frac{5-2x}{3x}\] Now you should find the function x(y). In other words, put x in function of y. An example with other function: \[f(x)=2x+3\\ y=2x+3\\ x=(y-3)/2\] Then change x for y, and y for x this way, \[y=(x-3)/2\]But now, \[f^{-1}(x)=(x-3)/2\]
But the answer is \[\frac{ 5 }{ 3x+2 }\]
The answer I gave you was for an example. You should do the same process for your problem.
Do you understand it or need some more help?
yes please can u?
Ok, the, first, we will find x(y), \[y=\frac{5-2x}{3x}\Rightarrow 3xy=5-2x\Rightarrow3xy+2x=5\Rightarrow\\ \Rightarrow x(3y+2)=5\Rightarrow x=\frac{5}{2+3y}\] Now, simply change x for y, and y for x, and you'll obtain the result.
even i was getting the same thing but i wasn't know to change x for y and y for x
any way thanks a lot
Join our real-time social learning platform and learn together with your friends!