Can someone please help me with this trigonometry problem?
what's the problem?
Hang on, I'm trying to post it.
if you compare the values of f(x) at x = 0 and pi/2 what do you think about the rate of change ?
wouldn't it just me pi/2
for f(x) the change is 2 and for g(x) the change is 4
what about h(x)
- both in the interval 0 to pi/2
so which is greatest rate of change g(x) or f(x)
for h(x) work out uts value for x = 0 and x = pi/2
if x is 0 it would be 5?
@cwrw238
Can you just tell me the answer with detailed steps?? Because I have a couple questions just like this and I need to know how to do them, but I have to move on so I can keep waiting..
average rate of change of f(x) in the interval (a,b) is: f(b)-f(a)/b-a
x = 0 h(x) = 5 , x = pi/2 h(x) = 5
Chad123 has given you the formula for average rate of change
for f(x) the interval is pi/2,2 plug in the values in the formula
so in the case of f(x) average rate of change = (2 - 0) / pi/2
so the answer is g(x)
yes
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