Question

#1
the final burret reading mL is 31.12
initial buret reading mL IS 15.72
volume of titrant mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol

Answer 1

What do you need to find?

Answer 2

I need to find the moles of HC2H302 neutralized by the NaOH

Answer 3

how do i find this

Answer 4

Change in the reading of burette = 31.12-15.72=15.4

Answer 5

Moles of NaOH = weight/gram molecular weight => 1.568*10^-3=weight/40 => weight=6.272 * 10^-2

Answer 6

molarity of standardized NaOH solution is .012

Answer 7

ok Moles of NaOH used is 1.568*10^-3 mol



but now, I need to find the moles of HC2H302 neutralized by the NaOH

Answer 8

how do i find this

Answer 9

Do we know the molarity of HC2H3O2?

Answer 10

volume of dilluted vinegar used in each titration 20 ml .02

Answer 11

that is all they gave us

Answer 12

m1*v1 = m2*v2 => 0.12*15.4=m2*15.49 => m2 = 0.11

Answer 13

We got the molarity of HC2H3O2

Answer 14

molarity = moles/ ml =>moles = 0.11*15.49 = 1.7 moles

Answer 15

yes

Answer 16

At the starting we got it

Answer 17

Change in the reading of burette = 31.12-15.72=15.4

Answer 18

Yeah. I took it for approximation

Answer 19

No 0.09 difference

Answer 20

No. There will be a difference of about 0.01 moles I presume

Answer 21

No

Answer 22

what about this one


I need to find the moles of HC2H302 neutralized by the NaOH


final buret reading is 15.53
initial buret reading mL is 0.00
volume of titrant mL is 15.53
Moles of NaOH used is 1.57*10^-3

Answer 23

Use the before method

Answer 24

it it .12*15.5=m2*15.53

Answer 25

Yeah m2=0.12

Answer 26

No of moles = 0.12*15.53

Answer 27

1.8636

Answer 28

Yes

Answer 29

and aswer willbe to 4 sig figs

Answer 30

1.863

Answer 31

right