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Mathematics 9 Online
OpenStudy (anonymous):

I'll medal if someone helps me with this! The surface area of this pyramid is one hundred eighty-nine square centimeters. The area of the square base is forty-nine square centimeters. What is the area of one triangular face of the lateral surface? Show the steps of your solution and explain your work.

OpenStudy (anonymous):

OpenStudy (cwrw238):

since the base is a square the 4 triangles making up the sides are equal in area total area of the triangular faces = 189-49 = 140 cm^2 so the area of 1 face = ?

OpenStudy (anonymous):

I really don't mean to sound like an idiot, but what does the ^ in the problem mean? Other than that I believe I can solve it, just give me a minute.

OpenStudy (anonymous):

so 189-49 is 140...

OpenStudy (anonymous):

waiiit

OpenStudy (anonymous):

does this ^ mean squared? I think it does, sorry XD

OpenStudy (anonymous):

Is the area of face 1 140?

OpenStudy (cwrw238):

yes - square centimeters

OpenStudy (cwrw238):

140 cm^2 is the total area of the 4 faces

OpenStudy (anonymous):

so divide by 4?

OpenStudy (anonymous):

35!

OpenStudy (anonymous):

Thank you! Sorry you had to see the real idiotic side of me >.>

OpenStudy (cwrw238):

no 140 is the area of all 4 faces so area of any 1 face = 140/4

OpenStudy (anonymous):

but isn't 140/4 35?

OpenStudy (cwrw238):

yes 140/4 = 35 thats your answer each triangle has the area 35 cm^2

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