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Mathematics 13 Online
OpenStudy (darkbluechocobo):

Help with solving equations

OpenStudy (darkbluechocobo):

OpenStudy (darkbluechocobo):

@ganeshie8

OpenStudy (johnweldon1993):

So what we have is \[\large y = \frac{2}{5x + 3}\] And we want the inverse of this function \(\large f^{-1}(x)\)

OpenStudy (johnweldon1993):

So what we do, is switch the position of the 'x' and the 'y'....and then use algebra to solve for 'y' again

OpenStudy (johnweldon1993):

So \[\large x = \frac{2}{5y + 3}\] how would you solve that for 'y' again?

OpenStudy (darkbluechocobo):

y=2/5 +3 /x?

OpenStudy (darkbluechocobo):

or would you subtract x

OpenStudy (darkbluechocobo):

so y= 2/5 + 3 -x?

OpenStudy (johnweldon1993):

No we can just do simple multiplication here Multiply both sides by 5y + 3 \[\large x(5y + 3) = 2\] Divide both sides by 'x' \[\large 5y + 3 = \frac{2}{x}\] Now subtract 3 from both sides \[\large 5y = \frac{2}{x} - 3\] Lets simplify this a bit first...we need a common denominator (which would be 'x') \[\large 5y = \frac{2}{x} - \frac{3x}{x}\] can put that over the common denominator \[\large 5y = \frac{2 - 3x}{x}\] And finally divide everything by 5 \[\large y = \frac{2- 3x}{5x}\]

OpenStudy (darkbluechocobo):

can we do another one please t=t just to make sure it made sense

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