Question

s(x)=2x^2
t(x)=x^3



write the expression (t+s)(x) and (t*s)(x) and evaluate (t-s)(2).

Answer 1

medal and fan

Answer 2

\((t+s)(x)=t(x)+s(x)\)
\((t*s)(x)=t(x)*s(x)\)
\(t-s)(2)=t(2)-s(2)\)

so for example:
\((t+s)(x)+t(x)+s(x)=(2x^2)+(x^3)=2x^2+x^3\) no other simplification

Answer 3

last line should real: \((t+s)(x)\color{red}{=}t(x)+s(x)\)

Answer 4

what i don't get what your doing

Answer 5

@satellite73 @Hero @zepdrix

Answer 6

\(t(x)+s(x)\)... since \(t(x)=x^3\), and \(s(x) = 2x^2\)
\(t(x) + s(x) = x^3+ 2x^2\)

Maybe it's more clear now. I inverted the addition before but it doesn't matter, addition here is commutative :)

Answer 7

so how do I add it into the formula

Answer 8

that's all there is to do

Answer 9

\((t*s)(x)=t(x)*s(x)=x^3*2x^2\), this you can simplify more using exponent laws:

\(x^a*x^b=x^{a+b}\)