Question

@jim_thompson5910

Answer 1

Find a cubic function with the given zeros.

\[\sqrt{2}\],
\[-\sqrt{2}\], -2
f(x) = x^3 + 2x^2 - 2x + 4
f(x) = x^3 + 2x^2 + 2x - 4
f(x) = x^3 - 2x^2 - 2x - 4
f(x) = x^3 + 2x^2 - 2x - 4

Answer 2

since those are the zeros, we know

x = sqrt(2), x = -sqrt(2), x = -2

x^2 = 2, x = -2

x^2 - 2 = 0 or x+2 = 0

(x^2-2)(x+2) = 0

I'll let you finish

Answer 3

x^3+2x^2-2x-4

Answer 4

yes

Answer 5

Thank you!