Absolute Value Equations Does this problem have a solution that is equal to one another? |x + 4| = 3x + 2
there is only one solution here, although sometimes there are two
i got 2.5 = 2.5 but its supposed to be 2.5 = - 2.5 what did i do wrong?
first of all \(1\) is a solution "by instpecton" since it is pretty clear that \[|1+4|=3+2\]
\(2.5\) is not a solution
through my experience with absolute value always one answer is positive and one answer is negative but they're the same number
not true here however
im talkin about the negative side oops sorry forgot to mention that
?
i have for the positive x = 1 and 5 = 5 and for the negative i have x = 1.5 and 2.5 = 2.5
you lost me
|x +4| = 3x + 2 is the positive and |x + 4| = -3x - 2 is the negative
They will have the same magnitude, but opposing signs you mean.
if \(x>-4\) then \(|x+4|=x+4\) and you can solve \[x+4=3x+2\] easly
you get \[x=1\]
yea but the other side is negative for the second half of the problem
and its -1.5
careful here
and i plug it in
if \(x<-4\) then \[|x+4|=-x-4\] and lets see what happens when we solve \[-x-4=3x+2\]
we get \[4x=-6\] so \[x=-\frac{3}{2}=-1.5\] HOWEVER
we were making the assumption that \(x<-4\) and so \(x\) CANNOT be \(-1.5\) since \(-1.5>-4\)
conclude that there is only one solution \(x=1\) alternatively graph the line \(y=3x+2\) and the V shaped \(y=|x+4|\) and see that they intersect in only one place
wait you're losing me so x cant be greater than -4?
lets go slow
thats what she said
it is clear that if you solve \[x+4=2x+3\] you get \(x=1\) right actually she said "if you want to make me happy you gotta make it snappy"
yea i get that part
ok so then the other thing to solve is \[-x-4=3x+2\]
but \(|x+4|=-x-4\)
ONLY IF \(x<-4\) otherwise \(|x+4|=x+4\)
so when you solve \[-x-4=3x+2\] and get some number LARGER than \(-4\) it is not a real solution
wait u lost me with -x-4 = 3x+2 why did you do that?
because \(|x+4|\) is either \(x+4\) or its negative \(-x-4\) what two equation would you solve?
hey is that a rule? if the number is larger than the number all the way to the right that its a no solution?
i don't know if it is a rule, but it is true
i bet you were going to solve \[x+4=-3x-2\] right?
yea!!
why isnt that right???
well convince yourself that that is the same as solving \[-x-4=3x+2\]
just multiply both sides by \(-1\)
so go ahead, solve \[x+4=-3x-2\] and when you check your answer you will see it does not work !!
yea its not supposed to work the guy in the GRE video got 2.5 and a -2.5 thats the right answer
im tryna figure out how he got the 2nd negative cuz i keep gettin 2.5 for both
there is no \(2.5\) in it i see what you mean though once you solve, you get \[x=-1.5\] then substitute in to the original equation
yea!! thats what i did and it came out to be 2.5 for both sides
but its supposed to be -2.5 on the right side .... i don't kno how he got that
because you did not substitute in to the ORIGINAL equation \[|x + 4| = 3x + 2\] you substituted in to \[x+4=-3x-2\]
it is a solution to the second equation, but not to the first
wait i thought you were supposed to substitute the what you got from the negative to the negative problem?
you have to plug in both x=1 and x=-1.5 to the first equation not the second?
yes, you are solving \[|x + 4| = 3x + 2\] right ? that is what you have to check
forgot how much i liked george clinton
oh wth............. i did not know that.... i see it now
whew
now i am going to go listen to more funk later
nice !!
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