how does the formula of motion v^2 = v.^2+2at^2
derive from d=v.t + .5at^2 and v=v.+at

v=final velocity
v.= initial velocity
a= acceleration
t=time
d=distance

Question

how does the formula of motion v^2 = v.^2+2at^2
derive from d=v.t + .5at^2 and v=v.+at

v=final velocity
v.= initial velocity
a= acceleration
t=time
d=distance

anonymous · Answer

First of all, that equation makes no sense. Multiplying ' a ' by ' t^2 ' gives meters, which is not the unit of velocity.

The real equation is: v^2 = v.^2 + 2ad

If you would still like the derivation for this, look at the attachment.