Question

Solve the equation: p^2 =23 p -132

Answer 1

GO SEE THE ANSWER

Answer 2

go see the answer where?

Answer 3

do you know the quadratic formula?

Answer 4

yes

Answer 5

First rearrange it so it's equal to 0:
\[p^2-23p+132=0\]Then use the quadratic equation to solve for p:\[p=\frac{-b \pm \sqrt{b^2-4ac}}{2a} = \frac{-(-23) \pm \sqrt{23^2-4(1)(132)}}{2(1)} = \frac{23}{2} \pm \frac{1}{2}\] So p is 11 and 12

Because these are integers, you know you could have solved it by factoring, without the quadratic equation. It can be factored as:\[p^2-23p+132 = (p-11)(p-12)\] 11 and 12 would make these 0, so they are your roots.

Answer 6

thank you so much