Question

The least degree of the polynomial with real coefficients and with roots 2+i, 2i – 1 is 2

Answer 1

So what is the question?

Answer 2

this is true or false

Answer 3

Yes it is true

Answer 4

reason

Answer 5

Well I could try generating the original equation.

Answer 6

ROOTS = 2 + i and
2i -1

Is that right?

Answer 7

kk... i had send my assignment to u would u please solve this

Answer 8

you want me to solve this right?

Answer 9

plz sove this

Answer 10

yes plz i need your help...

Answer 11

(x -2 -1) * (x +1 -2i) = 0
x^2 +x -2ix -2x -2 +4i -x -1 +2i =0
x^2 -2x -2ix +6i -1 = 0
Well that's what I have so far

Answer 12

Are you absolutely sure of the roots?
Could you enter those again?

Answer 13

next question

it is true or false, give reason... If a statement has a direct proof, then it cannot be proved by contradiction.

Answer 14

I'm working on the first question

Answer 15

u have written -1 in place of -i

Answer 16

Yes I see that

Answer 17

next question

it is true or false, give reason... If a statement has a direct proof, then it cannot be proved by contradiction.

Answer 18

(x -2 -i) * (x +1 -2i) = 0
x^2 +x -2ix -2x -2 +4i -ix -i +2i^2 =0
x^2 -x -3ix -3i + 2i^2 -2 =0
Is that right?

Answer 19

ya... answer next

Answer 20

it is true or false, give reason... If a statement has a direct proof, then it cannot be proved by contradiction.

Answer 21

2i^2 = -2 So
x^2 -x -3ix -3i -4 =0

Answer 22

next question

it is true or false, give reason... If a statement has a direct proof, then it cannot be proved by contradiction.

Answer 23

false my dear

Answer 24

a statement can be proven using direct proof and contradiction reasoning
or even sometimes with other proves