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2i + (x + yi) = 6, what is x + yi?
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x+yi=complex number
yes
you wanna find x?
and yi
aaah wou wanna find x+yi
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yes. I don't unserstand
note x+yi=z 2i+z=6 \[(2i=6-z)|^{2}\] note that i^2=-1 \[-4=36-12z+z^2\] \[z^2-12z+32=0\] with the solutions \[z _{1}=4;z _{2}=8\]
so x+yi can be 4 or 8
I see thank you!
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