Question

The Kw of water varies with temperature. Calculate the pH of water at 30⁰C with a Kw = 1.469 x 10-14. Show all calculations leading to an answer.
@girlover @iceicebaby

Answer 1

plz i am so stuck

Answer 2

Kw=[H+]*[OH-] Kw=x^2 x=[H+]=[OH-]=(1.469*(10^(-14)))^(1/2)
pH=-log[H+]

Answer 3

\[Kw=\sqrt{1.469\times10^{-14}}\]

Answer 4

got it?

Answer 5

\[\left[ H ^{+} \right]=\sqrt{1.469 \times 10 ^{-14}}\]
\[pH=-\log[H ^{+}]= - \log \sqrt{1.469 \times 10 ^{-14}}= 6.92\]

Answer 6

i'm not a calculator but i think that manner is right.