My math teacher and I can't figure this problem out please explain steps. Determine the vertex of the given equation. y = -3x2 - 8x - 4
When using the quadratic formula, the x-coordinate of the vertex of a parabola can be found from \[\frac{-b}{2a}\] So in your case, the equation looks like: \[-3x^{2}-8x-4\] What do a and b equal?
a= -3 b= -8 c= -4
Correct! So if you plug your a and b into -b/2a, you get the x-coordinate of the vertex :) Can you think of how you'd find the y-coordinate?
Yes and we came up with -4/3 for x coordinate now we just can't figure out how to get the y
Oh! Well, you have your equation \[y = -3x^{2} - 8x -4 \] And now, you have a value for x! So all you have to do is plug it into the equation to solve for y
we came up with 12 which isn't an option. We guessed 4/3 for the y answer
Ah, 4/3 is the correct answer. I think you guys may have dropped the negative in front of the 3?
\[-3 ( -\frac{4}{3})^{2} - 8 (-\frac{4}{3}) - 4\] \[= -3 (\frac{16}{9}) + \frac{32}{3} - \frac{12}{3}\] \[= -\frac{16}{3} + \frac{32}{3} - \frac{12}{3}\] \[= \frac{4}{3}\]
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