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Expand the following using either the Binomial Theorem or Pascal’s Triangle. (2x + 4)^3
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@ParthKohli
\[(2x+4)^3=\sum_{r=0}^3{ 3\choose r}(2x)^{3-r}(4)^r \\ = { 3\choose 0}(2x)^{3-0}4^0+{ 3\choose 1}(2x)^{3-1}(4)^1+{ 3\choose 2}(2x)^{3-2}4^2+{ 3\choose 3}(2x)^{3-3}(4)^3\]
Is that what I have to do?
That's using the binomial theorem, but yes. You can simplify the expression more by evaluating each binomial coefficient, since \[ {n \choose r}=\frac{n!}{r!(n-r)!}\] or by using Pascal's triangle
Thank you so much! The lesson didn't really explain either so I had no clue of what I was supposed to do.
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ah well yw :)
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