Solve the following linear equation:
I will put the equation below.
I think where I am going wrong is finding a least common denominator to try to get rid of the denominator.
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OpenStudy (anonymous):
Ok, well let's see what you have done so far.
OpenStudy (anonymous):
OpenStudy (anonymous):
So I factored the denominators to be (2x-5)(x+0), x, and 2(x-5)
OpenStudy (anonymous):
2x^2 - 5x -> x(2x-5)
4x - 10 -> 2(2x-5)
OpenStudy (anonymous):
ohh okay, that would make a lot more sense than (x+0) haha
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OpenStudy (anonymous):
=0)
OpenStudy (anonymous):
okay let me work through it again and see what i get. I'll tag you when im done or if i have questions :)
OpenStudy (anonymous):
Okay, @Cosmichaotic i'm still doing something wrong.. haha.
Would the LCD be 2x(2x-5)?
OpenStudy (anonymous):
Yea, I think so!
OpenStudy (anonymous):
You gotta make each denominator = 2x(2x-5) by multiplying the numerators by the missing components of that denominator.
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OpenStudy (anonymous):
If I remember correctly.
OpenStudy (anonymous):
we were told to multiply the LCD by the numerator and cancel the denominators out, so that you aren't dealing with fractions