Question

show that the conjecture is false by finding a counter example. For any real number x, x^3 > or equal to x^2. is x as 1/4 a liable answer?

Answer 1

Well, you can check!
\[ \left( \frac{1}{4} \right)^3 = \frac{1}{64} \]
\[ \left( \frac{1}{4} \right)^2 = \frac{1}{16} \]
and
\[ \frac{1}{64} < \frac{1}{16} \]
So you're correct :)