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OpenStudy (anonymous):
calculate the specific heat j/gc for 50.2g sample of a metal that absorbs 355j when tempture increases 35.0c to 57.9c
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OpenStudy (julian.pitalua):
Start with the equation for heat absorbed of expelled.... Q= Specific heat x Mass x Temperature change then... Specific heat= Q/mass x temperature change Replacing... \[Specific heat= 355J \div (50.2 g \times (57.9 º C - 35.0 º C)= xxx J / g \times ºC\]
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