Question

Molarity of standardized NaOH solution is 0.1012
final buret reading, mL IS 31.21
INITIAL buret reading, mL IS 15.72
VOLUME OF TITRANT, mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol
Moles of HC2H302 neutralized by the NaOH is 1.568*10^-3 Mol
Molarity of dill HC2H302 is .0783


what is the deviation di?


what is the

Answer 1

hi aaronq how are you

Answer 2

do you know how to find the devaiton di, i need help

Answer 3

hey, i'm good. how are you?

what does "di" mean in "what is the deviation di?"

Answer 4

no i think diluted

Answer 5

volume of dilluted vinegar used in each titration is 20 mL .02 L

molarity of standardized NaOH solution is 0.1012 M

Answer 6

You need to know the "true value" to find the deviation. The general formula of deviation is:

\(\sf deviation=\dfrac{|true~value- experimental ~value|}{true~value}\)

Answer 7

so the true value is

Answer 8

you would have to be given it, or calculated it from other data.

Answer 9

as there were four titrations we did in the experiment, and we had to find the avarage molarity of diluted vinegar which i found and it was .07865M

Answer 10

so take this as the true value. Unless they're asking for the standard deviation, then you would have to do something more complicated.

Answer 11

the average is the true value

Answer 12

deviation = .07865-.0783 /.07865

Answer 13

yep that's good.

They probably want "percent deviation", so multiply this by 100 and add a % sign.

Answer 14

is it the average which is .07865 divided by Molarity of dill HC2H302 which is .0783 over average again

Answer 15

no they just said "what is the deviation di?"

Answer 16

so answer is 1.00446998

Answer 17

nope, your value should be very small because it's close to the true value - recall that deviation means "how far off the true value is my experimental value".

deviation = .07865-.0783 /.07865=0.00445009

Answer 18

@aaronq and do we round off to how many sig figs

Answer 19

you know, i think they want just this:

deviation = .07865-.0783

Answer 20

.00035

Answer 21

are you sure they would want just that

Answer 22

i mean my teacher did not relly go over how to caculate deviation

Answer 23

but you said deviation=|true value-experimental value|true value

Answer 24

yeah, i'm pretty sure that's what they want. It can be, there are different ways to express it

Answer 25

i would write 0.000350 to get the right number of sig figds

Answer 26

now how do i calculate

average deviation, D

Answer 27

look up mean deviation of sample

Answer 28

http://www.mathsisfun.com/data/mean-deviation.html

Answer 29

MEAN is another way of saying AVERAGE

Answer 30

if you read the information in the link you will learn that

Answer 31

you are just calculating the data
he probably got frustrated

Answer 32

Why do you keep tagging me when you already are being helped?

Answer 33

http://www.vitutor.com/statistics/descriptive/average_deviation.html

Answer 34

Look at the example on that website

Answer 35

@Brainybeauty

Answer 36

how do i calculate
average deviation, D
Do you know?

Answer 37

@Night-Watcher

Answer 38

@aaronq gave you the formula. You should be able to get your answers using that,

Answer 39

So what do you have to find out in that?

Answer 40

the formula i thinks to find the average deviation is \[\pm \sum_{?}^{?}(x _{1}-x _{ave})/n\]

Answer 41

there were 4 trials and the deviation was
.000350
.000150
.000250
.000250

Answer 42

Molarity of standardized NaOH solution is 0.1012
final buret reading, mL IS 31.21
INITIAL buret reading, mL IS 15.72
VOLUME OF TITRANT, mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol
Moles of HC2H302 neutralized by the NaOH is 1.568*10^-3 Mol
Molarity of dill HC2H302 is .0783
avearge molarity of diluted vinegar is 0.7865 M
the deviation di is .000350

Answer 43

Are you doing a chemistry practical right now?

Answer 44

yes lab question

Answer 45

delete your post on my question please

Answer 46

@Night-Watcher hlep me

Answer 47

i need to plug in the numbers in the equation