Question

4x-4 is greater than or equal to -3x^2 solve algebraically

Answer 1

start with
\[3x^2+4x-4\ge 0\]

Answer 2

then see if you can factor to find the zeros

Answer 3

OK

Answer 4

I cant get it

Answer 5

you get that last problem?

Answer 6

No i didnt get that one either

Answer 7

I need to find the solution set for this one

Answer 8

\[3x^2+4x-4\geq 0\\(3x-2)(x+2)\geq 0\]

Answer 9

zeros are at \(-2,\frac{2}{3}\) and since this is a parabola that faces up, it will be positive outside the zeros

Answer 10

two intervals
\[(-\infty,-2]\cup [\frac{2}{3},\infty)\]

Answer 11

so what is the solution set be

Answer 12

then ones i wrote above

Answer 13

what about use the remainder hteorem to find the remainder when f(x) is divided by x-1 than factor the theorem to determine whether x-1 is a factor of f(x)=2x^4-5x^3+4x-1

Answer 14

remainder is \(f(1)\)

Answer 15

i.e.
\[2-5+4-1=0\]

Answer 16

and since \(f(1)=0\) that makes \(x-1\) a factor of
\[2x^4-5x^2+4x-1\]

Answer 17

Do you have time to keep helping me?