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Mathematics 19 Online
OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

The formula\[P=P_{0} \left(\begin{matrix}1 \\ 2\end{matrix}\right)^{h/4795}\] is the atmospheric pressure, P, in mm of mercury at elevation “h” meters above sea level. If P0 is 760 mm, at what elevation is the pressure 42 mm?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@factor @IMStuck

OpenStudy (anonymous):

oops sorry given the value of p0 and P find h from the equation

OpenStudy (anonymous):

how do i do that

OpenStudy (anonymous):

first of all take logarithm on both side of the equation... put the values of p and p0 then find h

OpenStudy (anonymous):

got it??

OpenStudy (anonymous):

No

OpenStudy (anonymous):

i kinda just want the answer

OpenStudy (anonymous):

\[\log_{10}P =(h \div4795) \log_{10}(1/2) \]

OpenStudy (anonymous):

is that the answer

OpenStudy (anonymous):

now find h from above given equation .......................

OpenStudy (anonymous):

put values of P and P0 in it and find H

OpenStudy (anonymous):

P=42 and P0=760

OpenStudy (anonymous):

now help yourself ... to find h

OpenStudy (anonymous):

so how would you put it together to find H like idk if i divide or multiply something

OpenStudy (factor):

@jk24 is rite I mean we r not supposed to give u the answer only CLUES

OpenStudy (anonymous):

what is th =is then log10P=(h÷4795)log10(1/2)

OpenStudy (anonymous):

@iGreen

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