For the function defined by: f(x)={x^2, x1 Evaluate f(0)

Question

For the function defined by: f(x)={x^2, x<= 1
                                                   {2x+1, x>1
Evaluate f(0)

anonymous · Answer

what do you think?

anonymous · Answer

I'm not sure I tried f(0)={0^2, 0<=1
                                     {0+1, 0>1
and then I didn't know what to do from there

anonymous · Answer

it is not clear to you how to read the function

anonymous · Answer

it means $f(x)=x^2$ IF $x\leq 1$ and $f(x)=2x+1$ IF $x>1$

anonymous · Answer

No it isn't clear

anonymous · Answer

so if i want for example $f(5)$ first i ask whether 5 is larger than 1 or smaller than 1

anonymous · Answer

since $5>1$ i use the second formula and $f(5)=2\times 5+1=11$

anonymous · Answer

whereas if i want $f(-2)$ i see that $-2$ is less than $1$ so i use the first formula and $f(-2)=(-2)^2=4$

anonymous · Answer

Ohh Okay, I'm understanding a little bit more now

anonymous · Answer

$$  f(x) = \left\{
     \begin{array}{lr}
       x^2 & \text{if } x\leq 1\
       2x+1 &\text{ if }x>1
     \end{array}
   \right.$$

anonymous · Answer

missing the word "if"
so if you  want $f(0)$ since $0$ is less than 1, use the top formula

anonymous · Answer

so what do I do with the bottom formula ?

anonymous · Answer

How would I write the final answer?  @satellite73

anonymous · Answer

would it be f(0)=0< 1