Resistors R1,R2,R3 have the values 5ohms, 10 ohms 30 ohms respectively which have been connected to a battery of 12 V. Calculate (a) the current through each resistor (b the total current in the circuit c) the total circuit resistence
I think c
its not mcq ur supposed to solce a b and c
Ohhh okay so do you know Ohm's law?
I'm assuming the circuit is in parallel. Let's find total resistance. if it's series, it's just a matter of adding em up, which gives \[5+10+30=45\] Let's find the TOTAL current first, which is according to \[V=IR\] So \[12V=I times 45\] \[I = 0.27A\] Note that since there is only one path for the current to travel, the current through each of the resistors is the same. Therefore your answers to part A and B both are 0.27A.
Sorry, I assumed the circuit was in series*. Not parallel.
The answer to C, total resistance, is as calculated above, 45 ohms.
We need to know how the resistors are connected before we can answer the question. Was there a diagram with the question ?
umm no
From the context and the questions, I am believing they are connected in parallel. "Why" you may ask? First it implies that the resistors (all three) are connected to a battery. For each resistor to be connected to a battery it would be parallel because if in series one resistor would not have a connection to the battery.|dw:1410972936877:dw|The total resistance R=E/I = 12/4 = 3 amps.
Join our real-time social learning platform and learn together with your friends!