Question

Is there anyone on here willing to give me their email address to help me with a Physics worksheet? I do not feel comfortable posting the questions on here, someone please get back to me.

Answer 1

I promise you I am not looking for just answers, I need someone who is thorough in explaining Physics. Please help.

Answer 2

what grade r u in?

Answer 3

My teacher never responds back to me, it's hard doing this on my own at times.

Answer 4

oh sorry i can't help but i can try to get some one to help u:)

Answer 5

there's no need to be embarrased about posting your questions here, that's the whole point of the site : )
and i think it goes against the code of conduct to give out contact details (maybe)

Answer 6

I'd be ready to help, and yeah, as prof said, no need to be embarrassed.

I don't know if it's against the CoC or not.

Answer 7

i agree with him/her

Answer 8

Okay thank you guys. I will just ask away then.

How do you find the acceleration when you are given a mass, a coefficient of kinetic friction, and a force? Like what formula(s) do I use?

Answer 9

Well, the acceleration of a mass is given by (total force acting on mass)/mass
That is newton's second law.
Usually, the tricky part is figuring out just what the total force actually is.

Answer 10

Okay, Like the force is 285N and the mass is 42kg. The coefficient of kinetic friction is 0.18. In order to find the acceleration, would I do 285=42a to find the acceleration?

Answer 11

When you say 'the force is 285N', what force is that ? Which force do you mean ?

Answer 12

It just says a force being pushed along the floor

Answer 13

Ah okay, now I understand

Answer 14

Okay, let me break it down for you

Answer 15

The mass is feeling a force pushing it forward, the 285 N, but it will also experience a frictional drag force in the opposite direction.
So the net force producing the acceleration is 285-drag force.
Okay so far ?

Answer 16

Okay so the net force is 285?

Answer 17

No, we have to figure out the drag force and subtract it from the 285

Answer 18

That's the next part . . . .

Answer 19

look back at my diagram that i posted a few messages ago
The normal reaction will be equal in size to the weight of the mass, which will be 42kg multiplied by 9.8, the acceleration due to gravity
Then to figure out the drag force, you multiply the normal reaction force by the friction coefficient.

Answer 20

so the friction force in you question will be 0.18 *(normal reaction)

Answer 21

I am with you still, I am just trying to do what you said on a piece of paper

Answer 22

ok, me too

Answer 23

I got 74.1636, i hope i did that right

Answer 24

that's what i have for the drag force, yes

Answer 25

so now you can easily find the net force pushing the mass forward, i.e. the applied force minus the drag force

Answer 26

210.8364 and rounded would be 211? so i plug in 211 for the equation F=ma in order to find the acceleration?

Answer 27

yes, you got it

Answer 28

Thank you very much, that makes sense. Could you help me with 2 more?

Answer 29

I'm willing to try, just post as separate threads

Answer 30

Alright and tag your name in them?

Answer 31

if you like, it helps me to find the question if i fall asleep

Answer 32

Alright, thank you :) I am going to post them within a couple minutes