No, I believe you are wrong.
\[2x+4=3x-11\]So now, just subtract 2x from both sides, which will get you...\[4=x-11\](remember 1x equals x) Now, you want to add 11 to both sides which will get you...\[15=x\]
undeadknight26 (undeadknight26):
Mind blown :D
Thanks!
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OpenStudy (hugsnotughs):
A pleasure.
undeadknight26 (undeadknight26):
One more?
OpenStudy (hugsnotughs):
Of course, Mr. Grey.
undeadknight26 (undeadknight26):
OpenStudy (hugsnotughs):
This one actually seems really hard, but it is actually pretty simple! Find the LCD for both fraction-equations or whatever the hell you want to call them.
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undeadknight26 (undeadknight26):
the lowest common denomiator would be 2 @hugsnkisses ?
undeadknight26 (undeadknight26):
Wrong person @hugsnotughs
OpenStudy (hugsnotughs):
No, the LCD is six. Remember, Least COMMON Denominator. :)
OpenStudy (mathmath333):
ita LCM (least common multiple)
OpenStudy (mathmath333):
LCD-->liquid crystal diode
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undeadknight26 (undeadknight26):
*stares* Im confused and my brain is hurting ;-;
OpenStudy (mathmath333):
multiply both sides by 6 and solve further
OpenStudy (hugsnotughs):
^
OpenStudy (hugsnotughs):
The 6 will take out the fractions..
undeadknight26 (undeadknight26):
Can you show me? Im confused ;-;
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