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OpenStudy (anonymous):
\[100=108(\sqrt{69}/9)^t\]
OpenStudy (anonymous):
What have you done so far?
OpenStudy (anonymous):
Do you know logs?
OpenStudy (anonymous):
I do but i've always had a problem with them so im stuck here it was a newton law of cooling equation that i got down to this and forgot how to solve for t
OpenStudy (anonymous):
would you just take the log of both sides or what's the first step
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OpenStudy (anonymous):
It's pretty simple if you apply logarithmic rules:
\[\log(100/108)=t(\log((\sqrt69)/9))\]
OpenStudy (anonymous):
Then you just divide the left side by \[\log((\sqrt69)/9)\]
OpenStudy (anonymous):
to get t
OpenStudy (anonymous):
Makes sense I just need to brush up on my log rules I was most confused by just the first step.
OpenStudy (anonymous):
Okay, glad to help then :)
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OpenStudy (anonymous):
when you plugged it in did you get .95?
OpenStudy (kirbykirby):
yeah it should give around 0.95996
OpenStudy (anonymous):
I plugged it back into the equation afterwards and the left side and right sides equaled each other too.