Question

Simplify 9 a cubed minus 12 a squared plus 6 a all over negative 3 a

Answer 1

\[\large \frac{9a^3 - 12a^2 + 6a}{-3a}\]

Factor out an 'a' from the numerator

\[\large \frac{a(9a^2 - 12a + 6)}{-3a}\]

Now also notice how every number in the numerator is dividable by 3 (so lets factor our a -3 here)

\[\large \frac{-3a(-3a^2 + 4a -2)}{-3a}\]

Why did I factor out -3? well

\[\large \frac{\cancel{-3a}(-3a^2 + 4a -2)}{\cancel{-3a}}\]

So what we're left with is \(\large -3a^2 + 4a - 2\)

Answer 2

Thanks

Answer 3

No problem! Did everything make sense? :)

Answer 4

Yes, i just get confused on theese problems. And never know where to start.