Help please?
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Question

Help please?
Image below!

undeadknight26 · Answer

attachment

johnweldon1993 · Answer

f(x) lets find the slope first

$$\large m = \frac{y_2 - y_1}{x_2 - x_1}$$

yanasidlinskiy · Answer

^amazinger than me!

johnweldon1993 · Answer

After that, we plug that slope and any 1 of those points we are given into the point slope form

$$\large y - y_0 = m(x - x_0)$$ this will give us the equation of the line we want

undeadknight26 · Answer

1 - (-7)/  1 - (-1)

undeadknight26 · Answer

y - 1 = 4(x - 1)?

johnweldon1993 · Answer

Great

and so that would be

$$\large y = 4x - 3$$ correct?

undeadknight26 · Answer

Roger!  showing f(x), h(x) and j(x) have the same slopes

johnweldon1993 · Answer

Ahh are we sure about that?

look at h(x) again

undeadknight26 · Answer

Crackers n cheese!  its a negative...

johnweldon1993 · Answer

hahaha indeed^

so it looks like only f(x) and j(x) have the same slope..

what can we say about g(x) and h(x) ?

undeadknight26 · Answer

g(x) has the highest and h(x) has the lowsest?

johnweldon1993 · Answer

hmm, what can you tell me about the slope of g(x) ? what is the slope?

undeadknight26 · Answer

g(x) = 
(0,3) (-2,5)
5 - 3/ -2 - 0
2/-2 = -1

undeadknight26 · Answer

Meaning its also a negative? Showing f(x) and J(x) to have the highest?

johnweldon1993 · Answer

(0,3) is a point on g(x) ?

undeadknight26 · Answer

Is it not?

johnweldon1993 · Answer

when x = 0 on g(x) where is y?

undeadknight26 · Answer

I forgot -3!  cruders!

johnweldon1993 · Answer

haha so lets see what the slope is again know that point was supposed to be (0, -3)

undeadknight26 · Answer

g(x) = 
(0,3) (-2,5)
5 - (-3)/ -2 - 0
8/-2 = -4!

johnweldon1993 · Answer

Ah ha! so now, what can we say about the slopes of g(x) and h(x)?

undeadknight26 · Answer

f(x) = j(x)
g(x) = h(x)?

johnweldon1993 · Answer

In terms of slopes that statement is correct...however I wouldn't write that unless you specifically say slopes!

johnweldon1993 · Answer

But to say f(x) = j(x) would say that those 2 lines are equal in terms of everything...as if they were the same line

johnweldon1993 · Answer

so now we can also compare the y-intercepts of the lines

undeadknight26 · Answer

So the b would be the changing factor at this point right?

johnweldon1993 · Answer

uhhh you're talking about

$$\large y = mx + b$$ right? if so then yes...the y-intercept shows differences between the lines

undeadknight26 · Answer

Aye capn!  Alright...I think i got it from here though...Thanks for helping me with the tough part though!

johnweldon1993 · Answer

Not a problem!