Please help. Calculate the amount of heat needed to boil 198.g benzene (C6H6), beginning from a temperature of 25.3 degrees C. Be sure your answer has a unit symbol.

Question

cuanchi · Answer

E= m x C x delta T
m= mass in moles or grams
C= specific heat per mol or grams
delta T= the difference of T between the boiling point of the benzene and 25.3C. 
You will need the C and the boiling point of the benzene, look in some table in internet

cuanchi · Answer

boiling point= 80.1C
specific heat capacity = 134.8 J/mol K
the delta T you can calculate it in C it will be that same that if you do it in K

aaronq · Answer

you also need to take into account the latent heat of vaporization. 

your formula would be a bit extended to:  $q=m*C_p*\Delta T+H_{vap}*m$

depending on the units of Hvap, you would use mass or moles.

cuanchi · Answer

The problem ask the necessary heat to boil the sample, not to evaporate all the sample. I am not sure if you have to include the vaporization heat term

aaronq · Answer

"boiling" implies that it's entering the gas phase, otherwise it would say "heat to boiling point".

cuanchi · Answer

yea you are right!! I haven't think in that way

anonymous · Answer

Thank you guys. Always to the rescue @aaronq :)