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Mathematics 15 Online
OpenStudy (jessicawade):

PLEASE HELP ME LEARN THIS

OpenStudy (jessicawade):

Birth weights in Norway are normally distributed with a mean of 3570 g and a standard deviation of 500 g. Find the probability that 100 randomly selected birth weights have a mean between 3500 g and 3600 g.

OpenStudy (jessicawade):

its the central limit theorem

OpenStudy (jessicawade):

if you know anyone who can help please tag them thanks :)

OpenStudy (kirbykirby):

\(n=100\), \(\sigma_{\overline{x}}=\dfrac{\sigma}{\sqrt{n}}=\dfrac{500}{\sqrt{100}}=50\) and \(\mu_{\overline{x}}=3570\) You are asked to find \(P(3500<\overline{X}<3600)\) By standardizing: \[Z=\frac{\bar{X}-\mu_{\overline{x}}}{\sigma/\sqrt{n}}\] \(P(3500<\overline{X}<3600)=\left(\dfrac{3500-3570}{50}< \dfrac{\bar{X}-3750}{50}<\dfrac{3600-3570}{50}\right)\\ =P(-1.4<Z<0.6)\)

OpenStudy (kirbykirby):

Then the rest should be easy. \(P(-1.4<Z<0.6)=P(Z<0.6)-P(Z<-1.4)\)

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