PLEASE HELP ME LEARN THIS
Birth weights in Norway are normally distributed with a mean of 3570 g and a standard deviation of 500 g. Find the probability that 100 randomly selected birth weights have a mean between 3500 g and 3600 g.
its the central limit theorem
if you know anyone who can help please tag them thanks :)
\(n=100\), \(\sigma_{\overline{x}}=\dfrac{\sigma}{\sqrt{n}}=\dfrac{500}{\sqrt{100}}=50\) and \(\mu_{\overline{x}}=3570\) You are asked to find \(P(3500<\overline{X}<3600)\) By standardizing: \[Z=\frac{\bar{X}-\mu_{\overline{x}}}{\sigma/\sqrt{n}}\] \(P(3500<\overline{X}<3600)=\left(\dfrac{3500-3570}{50}< \dfrac{\bar{X}-3750}{50}<\dfrac{3600-3570}{50}\right)\\ =P(-1.4<Z<0.6)\)
Then the rest should be easy. \(P(-1.4<Z<0.6)=P(Z<0.6)-P(Z<-1.4)\)
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