Question

Insert arbitrary iceberg. Density of water 1.0g/cm3 and the density of the ice 0.92 g/cm3. What percentage of the iceberg was under water? Express as a percentage (not decimal).

Answer 1

In your case I think the answer will be 92% is underwater.

http://www.bsharp.org/physics/icebergs

So, the fraction of ice underwater, Vw/Vi, is given by the ratio of densities i/w=0.917. Over 90% of an iceberg's volume (and mass) is underwater.

As you can see, the convenient definition of the gram gives us a quick way to see how much of a floating substance lies below the surface of fresh water: the fraction is equal to that substance's mass density in g/cm³. Ice has mass density 0.917 g/cm³, so 91.7% lies below the surface of water. In fact, it isn't quite that, because icebergs are actually found on seawater, which is more dense than freshwater. But that's a minor detail.