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Mathematics 15 Online
OpenStudy (anonymous):

Few more questions, unfortunately. (MEDAL) http://gyazo.com/625ce63bceb4a14367d6640feb6f726d

OpenStudy (dangerousjesse):

I'm not clicking on any more freaking links today. Take a screenshot and attache the file.

OpenStudy (anonymous):

I swear on my life, this link is legit...

OpenStudy (dangerousjesse):

I don't care.

OpenStudy (anonymous):

Lovely.

OpenStudy (dangerousjesse):

Just send a screenshot of it, please :)

OpenStudy (anonymous):

If you're that paranoid, set your computer volume to 0 before looking? :(

OpenStudy (anonymous):

I'm not able to take screenshots on my computer, its why I use gyazo.

OpenStudy (dangerousjesse):

What kind of computer?

OpenStudy (anonymous):

@kirbykirby

OpenStudy (anonymous):

@undeadknight26

OpenStudy (anonymous):

Seriously, unless two step equations are classified as "scary links" then their legit.

OpenStudy (kirbykirby):

I think anne.jpg has scared everyone... oye

OpenStudy (anonymous):

Yep. :/

OpenStudy (kirbykirby):

Hm I don't agree with these ones sadly lol.

OpenStudy (anonymous):

Ah okay, well can you point me in the right direction?

OpenStudy (kirbykirby):

\[ \frac{1}{3}x=12\] If you just want \(x\) by itself, you can multiply both sides by 3, since \(\frac{1}{3}\cdot 3= \frac{3}{3}=1\)

OpenStudy (anonymous):

Is 1 the answer? If so, there is no answer choice for that.

OpenStudy (kirbykirby):

No. If you multiply both sides by 3, what you get is: \[ \frac{1}{3}x\cdot 3=12 \cdot 3\]

OpenStudy (kirbykirby):

Which implies \(x = 12 \cdot 3\)

OpenStudy (anonymous):

36.

OpenStudy (kirbykirby):

yeah

OpenStudy (anonymous):

Alright, and is my last one correct or also wrong?

OpenStudy (kirbykirby):

Wrong :s What you have is \(3x+3=21\) Subtract 3 from both sides: \(3x + 3 - 3 = 21 - 3\)

OpenStudy (anonymous):

18.

OpenStudy (kirbykirby):

\(3x = 18\) To isolate x now, divide both sides by 3

OpenStudy (anonymous):

6

OpenStudy (kirbykirby):

yep!

OpenStudy (anonymous):

Sweet, thanks once again!

OpenStudy (kirbykirby):

=]

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