Question

SOMEONE PLEASE HELP ALGEBRA 2

Answer 1

Convert the equation you arrived at in question 2 into slope-intercept form. Make sure to include all of your work.

For question two
i got x + 1y = 0

Answer 2

should i explain question two first?

Answer 3

You don't have to, just thinking.

Answer 4

Slope-intercept is y = mx + b where m is slope and b is y-intercept.
Essentially solve for y.

x + 1y = 0
x + y = 0
y = 0 - x
y = -x + 0
y = -x

Answer 5

my coordinates were (1,2) & (0,3)

I used (0,3) for question two

Answer 6

the equations you got are incorrect, unfortunately

Answer 7

(0, 3) is not a point on the line y = -x

Answer 8

slope intercept is solving for y and having it in y = mx + b. your equation is not correct for the point-slope form.

Answer 9

neither is (1, 2)

Answer 10

okk look imma explain question number two

Answer 11

2. Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A.

Launch area (1,2)
Point A (0,3)

For the slope i got 1

Standard Form - Ax + By = C

i got x + 1y = 0

Answer 12

did i get it right?

Answer 13

so to get from (1, 2) to (0, 3) what does the spacecraft have to do? that is, how far up or down and how far left or right does it have to move?

Answer 14

go up

Answer 15

how much?

Answer 16

1 left 1 up ?

Answer 17

right

Answer 18

sorry, my pic is wrong... i'll repost with correct

Answer 19

did i get number two right?

Answer 20

but now you have to adjust for which points the line actually goes through.

the slope = rise/run = 1/-1 = -1 = m

y=-x+b plug in a known point and solve for b (the y-intercept) or realize that one of the points is the y-intercept (hint, when x = 0). then you'll have slope-intercept form.

to get standard form, simply move the x and y to one side of the equation and leave any numbers not associated with x or y on the other side.

Answer 21

rise = 1 because you go up 1 and run is -1 because you go left 1 (left is the negative direction for the x axis).

Answer 22

so my slope intercept form would be y = -1(1- 2)

Answer 23

bc i used the point (1,2)

Answer 24

no... y = mx+b is slope-intercept form but you need numbers for m and for b.

what is the value of m?

Answer 25

-1

Answer 26

good. now do you know the value of b?

Answer 27

2?

Answer 28

nope. do you know how to find the value of b?

Answer 29

no please help

Answer 30

sure! so first we rewrite the slope-intercept form witth what we know (m, at this point). then we get:

y = -1*x + b
or
y = -x +b

now we use a point on the line to help us find the value of b. do you know a point on the line? if so, which one would you like to use?

Answer 31

(1,2)

Answer 32

okay, so (1, 2). x = 1 and y = 2. we plug those values into or equation and then solve for b.

like this:

y = -x +b => (2) = -(1) + b => 2 = -1 + b add 1 to both sides to get

3 = b


so our slope-intercept form is y = -x + 3

do you follow all of that?

Answer 33

yess

Answer 34

you can always check that it works for the points you know on the line. for example, when x = 0, what does the equation tell us y should be?

Answer 35

0 right?

Answer 36

nope. put in 0 for x in the equation we just got.

Answer 37

3

Answer 38

y = 0 + 3

Answer 39

there you go! now is the point (0, 3) a point on the line?

Answer 40

yesss!

Answer 41

great! what about when x = 1... what is y? again, use the equation.

Answer 42

4

Answer 43

try again

Answer 44

3 ?

Answer 45

nope...

y = -(1) + 3 = ?

Answer 46

2

Answer 47

i didnt use the negative thats why

Answer 48

there you go! now is (1, 2) a point on the line?

Answer 49

yess

Answer 50

thank you so much!! you are a very big help <3

Answer 51

so you have the right slpe-intercept form for your line!

Answer 52

do you know how to find the standard form?

Answer 53

Yes i do

Answer 54

so what is the standard form you got?

Answer 55

i had got x + 1y = 0

Answer 56

so you can check that one too.

pick a point on the line.

Answer 57

(0,3)

Answer 58

so we plug in 0 for x and 3 for y and see if we get a true statement:

(0) + 1(3) = 0 + 3 = 3 \(\ne\) 0

so you don't have the correct standard form. do you want to know how to get the correct standard form?

Answer 59

no please help

Answer 60

Launch area (1,2)
point A (0,3)

find the slope
slope(m) = (y2 - y1) / (x2 - x1)
(1,2) x1 = 1 and x2 = 2
(0,3) x2 = 0 and y2 = 3

now lets sub
m = (3 - 2) / (0 - 1)
m = 1/1 = 1

if we use (1,2) the equation is x = 1
if we use (0,3), the equation is x = 0

standard form : x + 1y = 0

Answer 61

or would it be x + 1y = 3

Answer 62

start with the slope-intercept form we found that we know works...

y = -x + 3

now we simply get x and y on the same side. to do this, add x to both sides...

x + y = x + (-x) + 3 => x + y = 3

and there is the standard form. you can check your points to make sure it works.

check (0, 3) => (0) + (3) = 0 + 3 = 3 check!

check (1, 2) => (1) + (2) = 1 + 2 = 3 check!

Answer 63

yes! so i got it right the second time lol

Answer 64

yep, great! just follow those steps and you'll be good to go!