Find an equation of the tangent line to the graph of the function square root(x-2) at the point (18,4)
Start by finding the derivative.
Do you know how to do that?
yes but i must be doing my work wrong
What are you getting?
y=4/8x+16
... You are finding the derivative of \[\sqrt{x-2}\] correct?
Yes. I got 4/8 for the derivative and than I plugged it into this formula y-y1=m(x-x1)
Did you get \[\frac{ 1 }{ 2\sqrt{x-2}}\] for the derivative?
Before you plugged in 18
yes I did
Then you should've gotten 1/8, not 4/8?
oh okay i see what happened. Ok so that is the derivative which also equals the slope?
Yes. Are you getting the right answer now?
no. y-4=(1/8)(x-18) y-4=1/8x+9=4 y=1/8x+25/4
Where did the 9 come from in your second line? 18/8 =/= 9
Was that supposed to be a slash?
yes sorry
Alright, what does your book say the answer is supposed to be?
Also, you seem to have written 9/4 as positive instead of negative.
it is an online quiz the answers are: y=x/8+9/4 y=x/8+7/4 y=x/8+9/2 y=x/4+9/2 y=x/4+7/2
Yes, the answer is the second one. If you look at your work, you'll see that a negative's become a positive, which messed up your answer.
I see now thank you so much! :)
Np. :) Since this is apparently your first question, I'll ask you straight-out for a medal, if you understood my explanation.
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