The probability of a batch of 200 vaccines containing 0, 1, 2, 3, 4, or 5 ineffective vaccines is given in the following probability distribution. #16Q1.png What is the probability that a random batch of 200 vaccines contains at least 2 ineffective vaccines? a. 0.20 b. 0.35 c. 0.65 d. 0.80
Try to attach this picture #16Q1.png
At least 2 means \(P(X \ge 2)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\)
omg please stop with the anne pic >_<
ya I saw you deleted your reply
ok...so what am I supposed to do?
add up the probabilities ... i.e the y-value on your bar graph for x=2, x=3, x=4, x=5
@kirbykirby I add 0.05+0.1+0.15 etc? and then?
0.15, 0.10, 0.05 and 0.05
I am confused -.-"
Add the probabiltiies for ineffectiveness at x=2, x=3, x=4, x=5
At x=2, the probability s 0.15 at x=3, the probability is 0.10 at x =4, the probability is 0.05
at x=5 the probability is 0.05
got that.
I guess it's 0.35?
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