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Physics 7 Online
OpenStudy (anonymous):

A particle moves along a circle with a uniform speed v. After it has made an angle of 60 , the change in its speed and velocity will be

OpenStudy (anonymous):

@theEric

OpenStudy (theeric):

Do you already understand the main difference between speed and velocity?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

velocity would be constant , it would be v

OpenStudy (anonymous):

as it is uniform .......

OpenStudy (anonymous):

what would be its speed though

OpenStudy (theeric):

I would actually say it the other way around! Speed is a "scalar," which is to say that it doesn't concern direction or orientation at all! That's why roads have speed limits. They don't restrict your direction - they just restrict your rate of travel. Velocity has both a magnitude and direction. So, a speed and a direction of travel. So, velocity changes because the direction of this boring particle changes. Sorry, particle. Someone had to say it. You are no roller coaster... :P

OpenStudy (anonymous):

But v is given as the answer for velocity and 0 for speed

OpenStudy (theeric):

Well, it asks for the change in speed and velocity. It's odd that the change in velocity is the velocity. I'll have to think about that. But the speed is constant, so the change in speed is 0. So do you understand the speed part?

OpenStudy (anonymous):

yep

OpenStudy (theeric):

Okay! And the magnitude of the velocity is the same.... It's the speed.... So, with this circle...|dw:1411169144210:dw|

OpenStudy (anonymous):

why it won't change

OpenStudy (theeric):

The change in velocity....|dw:1411169256755:dw|

OpenStudy (theeric):

It does change, by \(\vec v\) I labeled \(\vec v_0\) as the original and \(\vec v\) as the final velocity. Is that okay?

OpenStudy (anonymous):

yes very much

OpenStudy (theeric):

Okay! :) So we need to look at the change in velocity. That is the final velocity minus the initial velocity. So I did some vector subtraction in the bottom of the last picture. Here it is: |dw:1411169593776:dw| Do you understand that? Or should I explain?

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