What is the binomial coefficent of the 5th term of (x + y)^10
how about you try solve it and show us what you know at least
go back to Pascal's triangle and there is actually a formula for it
Yes, I got 252 and I wanted to check to make sure it was right?
To determine the binomial coefficient for the fifth term in the expansion of (x + y)^10, I would start by finding the (n above r). To find the r value, which is the exponent/power x is being raised to in the fifth term, I subtracted 5 from 10 (the n value) to get 5. The n value is 10 because that is the exponent the binomial is being raised to. So the equation/whatever would be (10 above 5). The first step to solve that is to factor the factorials. 10!/5!5! = (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2)/(5 x 4 x 3 x 2 x 5 x 4 x 3 x 2). I cancelled out some of the numbers until I got 252 over 1. Can you check my work @nincompoop
I'm homeschooled and working out of a textbook that doesn't show the answer for this. As I'm homeschooled, it isn't due so answer whenever you can. I'd like to know if I'm doing this right. Thanks!
(x+y)^10 compare with (a+b)^n so.a=x,b=y,n=10,Now (r+1)^th=Tr+1=nCr,a^n-r,b^r where r+1=5,r=4,then put the above formula.
@tutulk is the answer 252? my work is above
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