Show that the elementary row operations do not affect the solution set of a linear system.
@ganeshie8 @jim_thompson5910
this may be of help https://www.math.ucdavis.edu/~linear/old/notes3.pdf
1) Exchanging rows is same as changing the order of given equations - it wont affect the solutions 2) Multiplying a row by a non zero constant is same as multiplying a nonzero constant to both sides of an equation - it wont affect the solution
3) Adding a multiple of a row to another row : \[\large (a_{j1} + ta_{k1})x_1 + (a_{j2} + ta_{k2})x_2 + \cdots + (a_{jn} + ta_{kn})x_n \] \[\large (a_{j1}x_1 + a_{j2}x_2 + \cdots + a_{jn}x_n)+ (a_{k1}x_1 + a_{k2}x_2 + \cdots + a_{jn}x_n) \] Clearly if a solution satisfies both the equations, it satisfies above combined equation also
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