find the slope of the curve y=x^2+x at x=3
if you could assist me i would greatly appreciate your effort.@amistre64 @ganeshie8 @myininaya @jim_thompson5910
@amistre64
Have you considered the 1st Derivative?
yes i beleive im doing it wrong as i get (3+h)^2+3-12/h and end up getting the slope to be six but thats not one of my choices
slope is nothing but derivative that is dy/dx so can you tell me what is derivative of x^2 + x ?
im not familiar with that formula as i have just begun calculus and we have only been taught the difference quotient of f at a. @tgawade
use this derivative of x^n = n * x^(n-1)
so can u tell me what is derivative of x^2 = --?
[(3+h)^2+3-12]/h is correct, how did you proceed ?
i simplified and got 6h+h^2/h
then i cancel the hs and got 6+h
then i pugged in zero and got 6
let me go through it again
should i have replaced both x's in x^2+x with 3+h instead of one
f(x+h) = (x+h)^2 +(x+h) so [(3+h)^2+3-12]/h is infact NOT correct
yes, thats correct, both "x"s in f(x), replace it by x+h
[(3+h)^2+3+h-12]/h
so you would get h(6+h+1)/h cancel hs then plug in o for h and get 7 for the slope correct
now you will get the correct answer :) oh you already did! yesss, 7 is correct slope :)
thank you for your assistance i appreciate your time and effort @hartnn @tgawade @tkhunny
welcome ^_^
i know the easiest way to solve this does anybody want to know ??????
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