Question

Can someone explain how to do this problem?

Calculate the wavelength in nm that would be emitted by an electron in a helium ion (He+) falling from n = 6 to n = 4

Thanks

Answer 1

it is a two steps calculation, first you have to calculate the energy released by the electron falling from 6 to 4 and then calculate the wavelength associated to that energy

Answer 2

\[\Delta E= -2.18 \times10^{-18}J(\frac{ 1 }{ n _{f}^{2} }-\frac{ 1 }{ n _{i}^{2} })\]
\[E= h c/\lambda \]
\[\lambda =E/(hc)\]