A solution of 56% fertilizer is to be mixed with a solution of 25% fertilizer to form 155 L of a 51% solution. How many liters of the 56% solution must be used?

Question

anonymous · Answer

To create a breakfast beverage, cherry juice in two concentrations, 19% and 60%, must be combined into a solution that will be mixed with another type of juice to produce the beverage. If 70 gallons of 19% juice is used, how many gallons of the 60% juice must be used to obtain a 50% cherry juice solution?

dumbcow · Answer

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From this table we get 2 equations:
$$x + y = 155$$
$$56x + 25y = 51(155)$$
solve with substitution
--> y = 155 - x
plug into 2nd equation
--> 56x + 25(155-x) = 51(155)
solve for x

dumbcow · Answer

*sorry i switched the 51 and 56 in the table

anonymous · Answer

hmm I think I understand it

anonymous · Answer

so x= 130 I solved for x

dumbcow · Answer

ok good and you can use this table for any of these type of mixing questions
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dumbcow · Answer

yes x = 130
good job