Question

f(x)=[(x+3)/2][x^2-4x+9] I need to find its derivative using product rule , Please Help !

Answer 1

then use the product rule ... whats the hold up?

Answer 2

how can i find its derivative ?

Answer 3

what is the product rule?

Answer 4

u'(x).v(x) + v'(x)u(x)

Answer 5

u'(x).v(x) + v'(x).u(x)

Answer 6

looks right

so lets just use that

you have pretty simple u and v

Answer 7

whats your attempt look like?

Answer 8

Attempt means? final answer?

Answer 9

attempt means, you need help but you know the product rule so youve at least tried to work the problem. lets see what youve tried

Answer 10

U'= 1/2
V'=2x-4
=(1/2)(x2-4x+9) + (2x-4)(x+3)/2

Answer 11

I simplified it and got the simplification as
3x^2 /2 - 4x - 3/2

Answer 12

I got 3x^2-3 all over 2. Check my work though for mistakes:
(1/2)(x2-4x+9) + (2x-4)(x+3)/2
(1/2)(x2-4x+9) + (2x-4)(x/2+3/2)
x^2/2-4x/2+9/2+2x^2/2-4x/2+6x/2-12/2
x^2/2-2x+9/2+x^2+2x-12/2
x^2/2+2x^2/2-3/2
2x^2+x^2-3
3x^2-3 all over 2 OR 3x^2/2-3/2

Hope this helps, let me know if you see any errors in my work.

Answer 13

Thanks :)