Question

Simplify the expression.

x times the square root of the quantity 64 x cubed, plus 2 x times the square root of x, plus 8 times the square root of the quantity 2 x

If the simplified expression is written in standard form, what is the leading coefficient?

Answer 1

\[x \sqrt{64x^3} + 2x \sqrt{x} + 8\sqrt{2x}\]

Answer 2

@zimmah can you help me?

Answer 3

sorry i was busy

Answer 4

wouldn't that be x?

Answer 5

oh wait, got to simplify it first, of course it's not just x, it threw me off for a moment

Answer 6

oh hey its alright

Answer 7

x*(64x^3)^(1/2) + 2x(x)^1/2 + 8(2x)^1/2

Answer 8

rewrite

8x^(2/2) *x^(3/2) + 2x^(2/2)*x^(1/2) + 8\(\sqrt{2}\)x^(1/2)

Answer 9

is that hard to read? because i'm a bit lazy to properly format it, but if it's hard to understand i'll just work it out for you properly

Answer 10

wait so what would the answer be?

Answer 11

not on that yet, just checking if you follow the steps i take

Answer 12

and if you can easily read it this way, or if i should format it properly

Answer 13

ok sorry im just anxious considering ive been working on this damn algebra for like 2 hours now because im really slow at doing math and i can read it

Answer 14

alright.

The reason why i wrote the x as x^(2/2) instead of just x, is because we have to simplify it and write it in standard form.

So

8x^(2/2) *x^(3/2) + 2x^(2/2)*x^(1/2) + 8*√2*x^(1/2)

makes

8x^(5/2) + 2x^(3/2) + 8*2^(1/2)*x^(1/2)

since x^(5/2) is clearly higher than the others, 8 is the leading coefficient.

If i was going to fast don't be ashamed to ask clarification

Answer 15

sorry for the ???? that's just a copy-pasted square root sign.

Answer 16

ok haha i was about to ask what that was

Answer 17

some equation as above, but copypasting messes up the format if there's latex commands in it

Answer 18

same*

Answer 19

you see what i did there or is there a step i need to clarify?

Answer 20

one second im writing it down on paper to see if i understand how you got it because it is a tiny confusing in that format

Answer 21

\[\Large x(64x^3)^{1/2} + 2x(x)^{1/2} + 8(2x)^{1/2}\]
\[\Large 8x^{2/2} *x^{3/2} + 2x^{2/2}*x^{1/2} + 8\sqrt{2x}\]
\[\Large8x^{5/2} + 2x^{3/2} + 8\sqrt{2x}\]

Answer 22

same steps, proper format this time

Answer 23

ok yea thats way better!

Answer 24

alright i think i understand how to get it

Answer 25

nice

Answer 26

it's not particularly hard, just some technique you need to be aware of :)

Answer 27

yea well its hard when your really bad at math :p haha

Answer 28

thank you man for your help

Answer 29

math takes practice more than anything, and often a good teacher helps a lot

Answer 30

could you help me on another problem? its my last problem left

Answer 31

i had the luck to have great math teachers most of my life, so i know a lot about it

Answer 32

sure

Answer 33

im going to post it and @ at you

Answer 34

ok