Evaluate the limit: limx→∞ (4x+5)/3
What do you get?
@geerky42 I honestly have no idea since there is no x on the bottom
What happened to the value of \(\dfrac{4x+5}{3}\) as x getting bigger and bigger?
@geerky42 is it moving closer to 0?
really? What made you think that?
hard to explain. Am I wrong? What's right? is it moving away from 0?
\(x→∞\) basically mean x getting closer and closer to infinity. So we have \(\displaystyle \lim_{x→∞}\dfrac{4x+5}{3}\), which mean the value of \(\dfrac{4x+5}{3}\) as x approaches to \(\infty\)
say x is start at 0. f(x) is 5/3, right? at x=1, f(x) = 9/3 = 3 at x=2, f(x) = 13/3 at x=3, f(x) = 17/3 Note how numerator grows?
Correct go on
ok, what happen to f(x) when x is becoming infinity?
if we keeping going on: x=5, ... x=6, ... \(\vdots\)
it becomes infinity?
Gotcha
So \(\displaystyle \lim_{x\rightarrow \infty}\dfrac{4x+5}{3} = \infty\)
thank you very much!!!
welcome
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