hai guys,can anybody help me? how many grams of HNO3 are required to prepare 500 ml of a 0.601 M HNO3 solution?

Question

zpupster · Answer

find the moles of HNo3

molarity of HNO3 = Moles of HNo3/ liters=.601M is given

moles HNO3 = Molarity* Volume in Liters (.5 L given)

lastly

grams of HNO3= Moles HNO3* molarmass(g/mol) of HNO3

anonymous · Answer

mass of HNO3 = ?
V = 0.5L
M.mass of HNO3 = 63.0067u
Molarity = 0.601

molarity = no of moles of solute/volume of solution in L
0.601 = no of moles of solute/0.5
no of moles of solute = 0.3005

mass of HNO3 = no of moles * M.mass
                       = 0.3005*63.0067
                        = 18.933g