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OpenStudy (anonymous):
Select true or false:
The function –3(x + 2)(x – 5)3 > 0, when x < –2 or x > 5.
geerky42 (geerky42):
Last one, i have to go soon sorry
OpenStudy (anonymous):
OpenStudy (anonymous):
okay(:
geerky42 (geerky42):
For this problem, you just have to use brain.
So we have \(x<-2\)
What do that tell us about \((x+2)\)
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OpenStudy (anonymous):
it would be true(:
geerky42 (geerky42):
is \(x+2\) always positive for \(x<-2\) ?
OpenStudy (anonymous):
no
geerky42 (geerky42):
Always negative, right?
OpenStudy (anonymous):
yes
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geerky42 (geerky42):
ok, so we have: \(-3(x+2)(x-5)^3>0 ~~\Longrightarrow~~(-)(-)(x-5)^3 > 0\)
-3 is always negative, obviously. and (x+2) is always negative. what about \((x-5)^3\) ?
OpenStudy (anonymous):
its always negative exceot when x is 6
OpenStudy (anonymous):
except
geerky42 (geerky42):
well, yeah, but at x<-2, x cannot be 6.
So we have three negative numbers multiplying together.
(-)(-)(-)>0
multiplying negative numbers get us positive:
(-)(-) -> (+)
So we have (-)(-)(-) -> (+)(-)
geerky42 (geerky42):
and (+)(-) is always negative
So is \((-)>0\)? is negative number larger than 0?
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OpenStudy (anonymous):
nope
geerky42 (geerky42):
yeah, so that function at x<-2 is false.
OpenStudy (anonymous):
oh so this would be false..
geerky42 (geerky42):
right
OpenStudy (anonymous):
so we dont even have to check the other one because its false
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