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Mathematics 22 Online
OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

Select true or false: The function –3(x + 2)(x – 5)3 > 0, when x < –2 or x > 5.

geerky42 (geerky42):

Last one, i have to go soon sorry

OpenStudy (anonymous):

OpenStudy (anonymous):

okay(:

geerky42 (geerky42):

For this problem, you just have to use brain. So we have \(x<-2\) What do that tell us about \((x+2)\)

OpenStudy (anonymous):

it would be true(:

geerky42 (geerky42):

is \(x+2\) always positive for \(x<-2\) ?

OpenStudy (anonymous):

no

geerky42 (geerky42):

Always negative, right?

OpenStudy (anonymous):

yes

geerky42 (geerky42):

ok, so we have: \(-3(x+2)(x-5)^3>0 ~~\Longrightarrow~~(-)(-)(x-5)^3 > 0\) -3 is always negative, obviously. and (x+2) is always negative. what about \((x-5)^3\) ?

OpenStudy (anonymous):

its always negative exceot when x is 6

OpenStudy (anonymous):

except

geerky42 (geerky42):

well, yeah, but at x<-2, x cannot be 6. So we have three negative numbers multiplying together. (-)(-)(-)>0 multiplying negative numbers get us positive: (-)(-) -> (+) So we have (-)(-)(-) -> (+)(-)

geerky42 (geerky42):

and (+)(-) is always negative So is \((-)>0\)? is negative number larger than 0?

OpenStudy (anonymous):

nope

geerky42 (geerky42):

yeah, so that function at x<-2 is false.

OpenStudy (anonymous):

oh so this would be false..

geerky42 (geerky42):

right

OpenStudy (anonymous):

so we dont even have to check the other one because its false

OpenStudy (anonymous):

thanks!!

geerky42 (geerky42):

make sense, right?

geerky42 (geerky42):

welcome

OpenStudy (anonymous):

yes!

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