please explain (: @hartnn
it is neither.
please explain?
another way to find it out is drawing it out.
is there any way to figure it out from like an equation?
Yes, there are. By plugging x by -x into the function Definition of even: f(x) = f(-x) odd : f(-x) =-f(x) Now, figure out all of them:
YOur f(x) = \(\sqrt {2x+1}\) right?
Is it f(x) = \(2\sqrt{2x+1}\) I need find 1) -f(x) 2) f(-x) and then compare.
1) -f(x) is easy, just plug minus sign in the front, I get -f(x) = -\(2\sqrt{2x+1}\) got this part??
sorry my computer is acting up, it is this
ok, no problem, just find -f(x) f(-x) show me your -f(x)
-f(x)= -x-5/x
where is ^3?
-x^3-5/x
good, now replace all x in your original one by (-x) , what do you get? (it is f(-x))
it is the same thing..
Don't be lazy, have to label them. As above you have \(\color{red}{-f(x)}= -x^3-\dfrac{5}{x}\)
Show me your work with the name of the function \(\color {blue}{f(-x)}\)
im not! im confused!!
I know!! that's why I want you to do STEP BY STEP to NOT be confused anymore.
didnt i already replace the x's in the first part? thats what im confused about
Those are different steps. for the first part , you just put the minus sign in the front of f(x) to get -f(x) For this part, you replace x by -x They are not the same.
ohh!
For example: if f(x) = x^2 --> -f(x) = -x^2 but f(-x) = (-x)^2 = x^2 Trivially, they are not the same
but youre multiplying the x by - 3 times which makes it still -x^2-5/x
-x^3-5/x*
I told you!! write the whole thing!!! f(x) = x^3 + 5/x now put minus sign in the front to get -f(x) = -[ x^3 +5/x] = -x^3 -5/x and you are correct there. Now the second step. Replace x by (-x) into \(\Huge f(x) \) to get \(\Huge f(-x)\)
No question, just do. It will turn clear later.
f(-x)= x+5/x
nope!!
omg
i think cause its over this that im not understanding, because im not that stupid
\(f(\color{red}{x})= \color{red}{x}^3+\dfrac{5}{\color{red}{x}}\) \(f(\color{red}{-x})= \color{red}{-x}^3+\dfrac{5}{\color{red}{-x}}= \color{red}{-x}^3-\dfrac{5}{\color{red}{x}}\)
thats what i put!!!
ok so moving on haha
Yes, now compare. you have \((\color{red}{-}f(x))= \color{red}{-x}^3-\dfrac{5}{\color{red}{x}}=f\color{red}{(-x)}\) right? so?? by definition, is it odd or even?
even(:
right?..
You guess??? type out the definition of odd and even , please
wait so f(-x) and -f(x) was the same right?!
yes.
lol im not guessing if f(-x) =- f(x) then the function is odd if f(-x) = f(x) then the function is even
i said it was the same earlier!!!!! you said no!!!
it is odd
Hihihi... you jumped from this question to other one. You wrote the functions without label them. You made question on a mess and you expected me understand what you are saying. hihihihi Yes, you are correct. My boss.!!
such an easy question, took an hour lol
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